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5x+9=x^2+2x
We move all terms to the left:
5x+9-(x^2+2x)=0
We get rid of parentheses
-x^2+5x-2x+9=0
We add all the numbers together, and all the variables
-1x^2+3x+9=0
a = -1; b = 3; c = +9;
Δ = b2-4ac
Δ = 32-4·(-1)·9
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{5}}{2*-1}=\frac{-3-3\sqrt{5}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{5}}{2*-1}=\frac{-3+3\sqrt{5}}{-2} $
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